document.write( "Question 100296: Could someone please take the time to help me solve the question: Solve the following system of two linear equations by elimination: 3x – 4y = 13 and
\n" ); document.write( "3y + 2 x = 3.\r
\n" ); document.write( "\n" ); document.write( "Thank you, I really appreciate your help.
\n" ); document.write( "

Algebra.Com's Answer #73156 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Solve the following system of two linear equations by elimination:
\n" ); document.write( "3x – 4y = 13
\n" ); document.write( "3y + 2x = 3
\n" ); document.write( ":
\n" ); document.write( "Arrange the 2nd equation to be in the standard form like the 1st equation:
\n" ); document.write( "3x - 4y = 13
\n" ); document.write( "2x + 3y = 3
\n" ); document.write( ":
\n" ); document.write( "We will eliminate x,
\n" ); document.write( "multiply the 1st equation by 2,
\n" ); document.write( "multiply the 2nd equation by 3
\n" ); document.write( ":
\n" ); document.write( "6x - 8y = 26
\n" ); document.write( "6x + 9y = 9
\n" ); document.write( "---------------subtracting eliminates x, find y
\n" ); document.write( "0x - 17y = 17
\n" ); document.write( ":
\n" ); document.write( "-17y = 17
\n" ); document.write( "y = 17/-17; divide both sides by -17
\n" ); document.write( "y = -1
\n" ); document.write( ":
\n" ); document.write( "Substitute -1 for y in the 1st equation and find x
\n" ); document.write( "3x - 4(-1) = 13
\n" ); document.write( "3x + 4 = 13; minus a minus is a plus
\n" ); document.write( "3x = 13 - 4
\n" ); document.write( "3x = 9
\n" ); document.write( "x = 9/3
\n" ); document.write( "x = +3\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check both solutions by substitution in the 2nd equation:
\n" ); document.write( "3y + 2x = 3
\n" ); document.write( "3(-1) + 2(3) = 3
\n" ); document.write( "-3 + 6 = 3; confirms our solutions
\n" ); document.write( ":
\n" ); document.write( "Could you follow this OK?
\n" ); document.write( "
\n" );