document.write( "Question 1116632: Dolebear law states the relationship between the rate at which snowy tree crickets chirp and the air temp of their enviroment. The formula is: T=50 =N-40/4 where T is a temperature in degrees Farenheit and N is a number of chirps per minute. If T=58 degrees, find the number of chirps per minute. I'm showed the answer is 78 in my book, however I do not understand how this answer was solved. Please show me the steps to arrive at this answer.
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\n" ); document.write( "How do I solve for N?
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Algebra.Com's Answer #731539 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
The formula, if properly written, is T=50+(N-40)/4
\n" ); document.write( "which should appear, \"T=50%2B%28N-40%29%2F4\".\r
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\n" ); document.write( "\n" ); document.write( "To solve for N, just undo what has been done to it, and do this to BOTH sides of the equation. \r
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\n" ); document.write( "\n" ); document.write( "\"N=4%28T-50%29%2B40\"\r
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\n" ); document.write( "\n" ); document.write( "Given is that you have T=58. Substitute this and evaluate N.
\n" ); document.write( "72 chirps per minute.\r
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\n" ); document.write( "To see every step,\r
\n" ); document.write( "\n" ); document.write( "\"T=50%2B%28N-40%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"T-50=%28N-40%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"%284%29%28T-50%29=4%28N-40%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"4%28T-50%29=N-40\"\r
\n" ); document.write( "\n" ); document.write( "\"4%28T-50%29%2B40=N-40%2B40\"\r
\n" ); document.write( "\n" ); document.write( "\"4%28T-50%29%2B40=N\"\r
\n" ); document.write( "\n" ); document.write( "\"N=4T-200%2B40\"\r
\n" ); document.write( "\n" ); document.write( "\"N=4T-160\"\r
\n" ); document.write( "\n" ); document.write( "\"steps\"\"may\"\"vary\".
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