document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1116581>Question 1116581</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose $9,200 is invested in an account at an annual interest rate of 2.5% compounded continuously. How long (to the nearest tenth of a year) will it take the investment to double in size? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #731498 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=731498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose $9,200 is invested in an account at an annual interest rate of 2.5% compounded continuously. How long (to the nearest tenth of a year) will it take the investment to double in size?<BR>\n" );
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document.write( "A(t) = P(e^(rt))<BR>\n" );
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document.write( "2*9200 = 9200*e^(0.025t)<BR>\n" );
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document.write( "e^0.025t = 2<BR>\n" );
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document.write( "0.025t = ln(2)<BR>\n" );
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document.write( "t = ln(2)/0.025<BR>\n" );
document.write( "t = 27.7 years<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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