document.write( "Question 1116610: The length of a rectangle is six times its width.
\n" ); document.write( "If the area of the rectangle is
\n" ); document.write( "150
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\n" ); document.write( "yd2
\n" ); document.write( ", find its perimeter.
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Algebra.Com's Answer #731495 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "if given that the length \"L\" of a rectangle is six times its width \"W\", we have
\n" ); document.write( "\"L=6W\" ....eq.1\r
\n" ); document.write( "\n" ); document.write( "If the area of the rectangle is \"A=150\", we have\r
\n" ); document.write( "\n" ); document.write( "\"A=LW=150\"\r
\n" ); document.write( "\n" ); document.write( "\"LW=150\"...substitute \"L\" with \"6W\"\r
\n" ); document.write( "\n" ); document.write( "\"6W%2AW=150\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5E2=150%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"W%5E2=25\"\r
\n" ); document.write( "\n" ); document.write( "\"W=sqrt%2825%29\"\r
\n" ); document.write( "\n" ); document.write( "\"W=+5\"\r
\n" ); document.write( "\n" ); document.write( "and, \"L=6W\" =>\"L=6%2A5\" =>\"L=30\" \r
\n" ); document.write( "\n" ); document.write( "then,\r
\n" ); document.write( "\n" ); document.write( "\"P=2%28L%2BW%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=2%2830%2B5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=2%2A35\"\r
\n" ); document.write( "\n" ); document.write( "\"P=70\"\r
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