document.write( "Question 1116591: Segment AS is a tangent to circle center M at point S
\n" ); document.write( "If the radius of the circle is 5 and AM = 12 find AS
\n" ); document.write( "

Algebra.Com's Answer #731474 by greenestamps(13209)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "A radius to a point of tangency is perpendicular to the tangent, so MS is perpendicular to AS.

\n" ); document.write( "AM is then the hypotenuse of right triangle SAM, so

\n" ); document.write( "\"MS%5E2%2BAS%5E2=AM%5E2\"
\n" ); document.write( "\"5%5E2%2BAS%5E2+=+12%5E2\"
\n" ); document.write( "\"25%2BAS%5E2+=+144\"
\n" ); document.write( "\"AS%5E2+=+119\"
\n" ); document.write( "\"AS+=+sqrt%28119%29\"
\n" ); document.write( "
\n" );