document.write( "Question 1116546: Solve over the interval [0, 2pi) : 3cot^2x-3cotx-1=0\r
\n" );
document.write( "\n" );
document.write( "I used the quadratic formula and got x=0.67, 1.83 and 4.97 \n" );
document.write( "
Algebra.Com's Answer #731465 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Solve over the interval [0, 2pi) : 3cot^2x-3cotx-1=0 \n" ); document.write( "--------- \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=================== \n" ); document.write( "tan(x) = 1/cot(x) \n" ); document.write( "tan(x) = 0.79128786 \n" ); document.write( "x = 0.90139, 4.04298 \n" ); document.write( "------------- \n" ); document.write( "tan(x) = -3.791288 \n" ); document.write( "x = 4.9703, 1.82869 \n" ); document.write( " \n" ); document.write( " |