document.write( "Question 100464: with of a rectangle is 3 inches less than one-half the lenght. what the lenght and width of the rectangle if the perimter is 36 inches. \n" ); document.write( "

Algebra.Com's Answer #73143 by doukungfoo(195) $\"\"$ $\"About$

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Perimete is equal to two times the length plus two times the width
\n" ); document.write( "OR
\n" ); document.write( " $\"P=2L%2B2W\"$
\n" ); document.write( "Given: perimeter is 36 inches
\n" ); document.write( "plug in 36 for the P
\n" ); document.write( "so
\n" ); document.write( " $\"36=2L%2B2W\"$
\n" ); document.write( "Given: the width is 3 inches less than 1/2 the length
\n" ); document.write( "so
\n" ); document.write( " $\"W=%281%2F2%29L-3\"$
\n" ); document.write( " $\"W=%28L%2F2%29-3\"$
\n" ); document.write( "Now plug in $\"%28L%2F2%29-3\"$ for the W
\n" ); document.write( "so
\n" ); document.write( " $\"36=2L%2B2W\"$
\n" ); document.write( " $\"36=2L%2B2%28%28L%2F2%29-3%29\"$
\n" ); document.write( "Now we can solve for L
\n" ); document.write( " $\"36=2L%2B2%28%28L%2F2%29-3%29\"$
\n" ); document.write( " $\"36=2L%2B%282L%2F2%29-6\"$
\n" ); document.write( " $\"36=2L%2BL-6\"$
\n" ); document.write( " $\"36=3L-6\"$
\n" ); document.write( " $\"42=3L\"$
\n" ); document.write( " $\"14=L\"$
\n" ); document.write( "So we have found the length equals 14 inches
\n" ); document.write( "We will use this to find the width
\n" ); document.write( " $\"W=%28L%2F2%29-3\"$
\n" ); document.write( " $\"W=%2814%2F2%29-3\"$
\n" ); document.write( " $\"W=7-3\"$
\n" ); document.write( " $\"W=4\"$
\n" ); document.write( "Now we have found the width equals 4 inches\r
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