document.write( "Question 1116508: A can of soda at 80° F. is placed in a refrigerator that maintains a constant temperature of 37°
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document.write( "F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by
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document.write( "T(t) = 37 + 43 e^– 0.058 t
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document.write( "Find the temperature of the soda 10 minutes after it is placed in the refrigerator. (Round to the nearest tenth of a degree.) \n" );
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Algebra.Com's Answer #731399 by Alan3354(69443) You can put this solution on YOUR website! T(t) = 37 + 43 e^– 0.058 t \n" ); document.write( "--------- \n" ); document.write( "It's T(t) = 37 + 43e^(–0.058t) \n" ); document.write( "Don't add spaces. \n" ); document.write( "========================== \n" ); document.write( "Sub 10 for t, use a calculator\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |