document.write( "Question 1116505: Express as an equivalent logarithm: log (x + 2) + log 1 – 3 log y \n" ); document.write( "
Algebra.Com's Answer #731397 by Alan3354(69443)\"\" \"About 
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Express as an equivalent logarithm: log (x + 2) + log 1 – 3 log y
\n" ); document.write( "log(1) = 0
\n" ); document.write( "log (x + 2) – 3 log y = \"log%28%28x%2B2%29%2Fy%5E3%29\"
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