document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1116473>Question 1116473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the perpendicular distance of the point (2, -1) from the line y= 3x+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #731384 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=731384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the perpendicular distance of the point (2, -1) from the line y= 3x+1<BR>\n" );
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document.write( "Find the perpendicular distance of the point (2,-1) from the line <BR>\n" );
document.write( "3x - y + 1 = 0<BR>\n" );
document.write( "a = 3<BR>\n" );
document.write( "b = -1<BR>\n" );
document.write( "c = 1<BR>\n" );
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document.write( "d = (ax + by + c)/sqrt(a^2 + b^2)<BR>\n" );
document.write( "d = (3*2 + 1 + 1)/sqrt(9+1) = 8/sqrt(10)<BR>\n" );
document.write( "d = 0.8*sqrt(10) </SPAN>\n" );
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