document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1116468>Question 1116468</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distribution of annual earnings of all bank tellers with five years of experience is skewed negatively. This distribution has a mean of Birr 15,000 and a standard deviation of Birr 2000. If we draw a random sample of 30 tellers, what is the probability that their earnings will average more than Birr 15,750 annually? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #731382 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=731382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The distribution of annual earnings of all bank tellers with five years of experience is skewed negatively. <BR>\n" );
document.write( "This distribution has a mean of Birr 15,000 and a standard deviation of Birr 2000. If we draw a random sample of 30 tellers, what is the probability that their earnings will average more than Birr 15,750 annually? <BR>\n" );
document.write( "z(15750) = (15750-15000)/(2000/sqrt(30)) = 750*sqrt(30)/2000 = 375*sqrt(30)/1000 = 0.375*sqrt(30) = 2.0540<BR>\n" );
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document.write( "P(x-bar > 15,750) = P(z > 2.0540) = normalcdf(2.0540,100) = 0.02<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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