document.write( "Question 1116432: Suppose P(A)=0.3 and P(B)=0.4 and P(A∩B)=0.12. Find:
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Algebra.Com's Answer #731353 by ikleyn(52782) $\"\"$ $\"About$

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\n" ); document.write( "Suppose P(A)=0.3 and P(B)=0.4 and P(A∩B)=0.12. Find:\r
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document.write( "a. P(B')                P(B') = 1 - P(B) = 1 - 0.4 = 0.6.\r\n" );
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document.write( "b. P((A∩B)')            P((A∩B)') = 1 - P(A∩B) = 1 - 0.12 = 0.88.\r\n" );
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document.write( "c. P((A∪B)')            First  P(A∪B) = P(A) + P(B) - P((A∩B) = 0.3 + 0.4 - 0.12 = 0.58\r\n" );
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document.write( "                        Then   P((A∪B)') = 1 - P(A∪B) = 1 - 0.58 = 0.42.\r\n" );
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document.write( "('=complement)\r\n" );
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