document.write( "Question 1116432: Suppose P(A)=0.3 and P(B)=0.4 and P(A∩B)=0.12. Find:
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document.write( "a. P(B')
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document.write( "b. P((A∩B)')
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document.write( "c. P((A∪B)')\r
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document.write( "('=complement) \n" );
document.write( "
Algebra.Com's Answer #731347 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Suppose P(A)=0.3 and P(B)=0.4 and P(A∩B)=0.12. Find: \n" ); document.write( "a. P(B') = 0.6 \n" ); document.write( "b. P((A∩B)') = 0.88 \n" ); document.write( "c. P((A∪B)') \n" ); document.write( "P(A or B) = 0.18+0.12+0.28 = 0.58 \n" ); document.write( "So, P(A or B)' = 0.42 \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |