document.write( "Question 1116413: Roland has in his coin purse quarters and $1 coins. He has four more quarters than dollar coins and the total value of the coins is $4.75. How many of each does Roland have? \n" ); document.write( "
Algebra.Com's Answer #731314 by greenestamps(13203) You can put this solution on YOUR website! \n" ); document.write( "(1) set aside the 4 \"extra\" quarters. Now he has equal numbers of dollar coins and quarters, and the total value is $4.75-$1 = $3.75. \n" ); document.write( "(2) one dollar coin and one quarter have a total value of $1.25. $3.75 is 3 times $1.25, so he has 3 dollar coins and 3 quarters. \n" ); document.write( "(3) bring back the 4 \"extra\" quarters. He now has the full total of $4.75, consisting of 3 dollar coins and 3+4=7 quarters. \n" ); document.write( "Algebraically.... \n" ); document.write( "let x = number of dollar coins \n" ); document.write( "then x+4 = number of quarters \n" ); document.write( "The total value of the coins is $4.75, or 475 cents: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The number of dollar coins is x = 3; the number of quarters is x+4 = 3+4 = 7. \n" ); document.write( "Note that the formal algebraic solution uses exactly the same arithmetic as the informal solution.... \n" ); document.write( " |