document.write( "Question 1116239: A market gardener in Tonga sells cabbages to a supermarket. She claims that the weights of the cabbages have a normal distribution with a mean weight of 1200 grams and a standard deviation of 50 grams.\r
\n" ); document.write( "\n" ); document.write( "(i) A cabbage is chosen at random, calculate the probability that its recorded weight is less than 1190 grams.\r
\n" ); document.write( "\n" ); document.write( "(ii) A consumer officer for the supermarket checks the gardener’s claim by weighing 40 of the cabbages. If the market gardener’s claim is true, calculate the probability that the 40 cabbages have a mean weight of less than 1190 grams.
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Algebra.Com's Answer #731304 by Boreal(15235)\"\" \"About 
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z=(x-mean)/sd
\n" ); document.write( "=(1190-1200)/50
\n" ); document.write( "=-.2
\n" ); document.write( "Probability z< -.2 is 0.4207
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\n" ); document.write( "for 40 cabbages the denominator is sd/sqrt(n)
\n" ); document.write( "z=(-10)/50/sqrt(40)
\n" ); document.write( "=-10*sqrt(40)/50=-1.26
\n" ); document.write( "Probability z < -1.26 is 0.1038
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