document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1116417>Question 1116417</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ladder is leaning against a building so that the distance from the ground to the top of the ladder is 2 feet less than the length of the ladder. Find the length of the ladder if the distance from the bottom of the ladder to the building is 6 feet.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #731301 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=731301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ladder is x<BR>\n" );
document.write( "It is x-2 feet up the building<BR>\n" );
document.write( "the distance from the bottom to the ladder is 6 feet<BR>\n" );
document.write( "Right triangle.<BR>\n" );
document.write( "square the sides: 6^2+(x-2)^2=x^2<BR>\n" );
document.write( "x^2=x^2-4x+4+36<BR>\n" );
document.write( "4x=40<BR>\n" );
document.write( "x=10 feet long ladder  ANSWER<BR>\n" );
document.write( "6 feet from building, 8 feet up<BR>\n" );
document.write( "6-8-10 right triangle<BR>\n" );
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