document.write( "Question 1116399: Given a+b=1, a^3 + b^3=16 and (a+b)^3 = a^3 +3a^2b +3ab^2 + b^3, find the value of a^2 + b^2. \n" ); document.write( "
Algebra.Com's Answer #731284 by Alan3354(69443)\"\" \"About 
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a+b=1
\n" ); document.write( "a^3 + b^3=16
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\n" ); document.write( "Sub 1-a for b
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\n" ); document.write( "a^3 + (1-a)^3 = 16
\n" ); document.write( "a^3 + 1 -3a +3a^2 -a^3 = 16
\n" ); document.write( "3a^2 - 3a - 15 = 0
\n" ); document.write( "a^2 - a - 5 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-1x%2B-5+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-1%29%5E2-4%2A1%2A-5=21\".
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\n" ); document.write( " Discriminant d=21 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--1%2B-sqrt%28+21+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-1%29%2Bsqrt%28+21+%29%29%2F2%5C1+=+2.79128784747792\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-1%29-sqrt%28+21+%29%29%2F2%5C1+=+-1.79128784747792\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-1x%2B-5\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-1x%2B-5+=+%28x-2.79128784747792%29%2A%28x--1.79128784747792%29\"
\n" ); document.write( " Again, the answer is: 2.79128784747792, -1.79128784747792.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-1%2Ax%2B-5+%29\"

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\n" ); document.write( "a = x1, b = x2 or vice versa
\n" ); document.write( "You do a^2 + b^2
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\n" ); document.write( "You'll find a^2 + b^2 = 11, so there is more than one way to do it.
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