document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1116363>Question 1116363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> susan invest 2 times as much money at 9% as she does at 6%. If her total interest after 1 year is $1440, how much does she invest at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #731251 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=731251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "...or here is a way to solve the problem with logical analysis instead of formal algebra<br><BR>\n" );
document.write( "The amount invested at 9% is 2 times the amount invested at 6%; and the 9% interest rate is 1.5 times the 6% interest rate.  Together those two things mean the interest earned at 9% is 2*1.5 = 3 times the interest earned at 6%.<br><BR>\n" );
document.write( "So 1/4 of the interest earned is from the 6% investment and 3/4 is from the 9% investment.<br><BR>\n" );
document.write( "1/4 of the total interest of $1440 is $360, so the amount of interest from the 6% investment is $360.<br><BR>\n" );
document.write( "And then the amount invested at 6% is $360/.06 = $6000.<br><BR>\n" );
document.write( "Then the amount invested at 9% is 2*$6000 = $12000. </SPAN>\n" );
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