document.write( "Question 1116305: A committee of 4 is to be chosen at random from among 5 women and
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Algebra.Com's Answer #731191 by Edwin McCravy(20055) $\"\"$ $\"About$

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A committee of 4 is to be chosen at random from among 5 women and
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document.write( "Case 1: 3 women and 1 man\r\n" );
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document.write( "Choose the 3 women 5C3 ways.\r\n" );
document.write( "Choose the 1 man 6C1 ways.\r\n" );
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document.write( "That's (5C3)(6C1) = (10)(6) = 60 ways for case 1.\r\n" );
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document.write( "Case 2: 4 women and no men\r\n" );
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document.write( "Choose the 4 women 5C4 ways.\r\n" );
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document.write( "That's 5C4 = 5 ways for case 2.\r\n" );
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document.write( "Answer: 60+5 = 65 ways.\r\n" );
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document.write( "Edwin

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