document.write( "Question 1116154: How do I find all the values to the following?
\n" ); document.write( "1) i^0.25
\n" ); document.write( "2) (1+sqrt(3)i)^(1/3)
\n" ); document.write( "3) (i-1)^0.5
\n" ); document.write( "4) ((9i)/(1+i))^(1/6)
\n" ); document.write( "

Algebra.Com's Answer #731095 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
The \"a%2Bi%2Ab\" form of complex numbers is not useful for calculating products, powers, and roots.
\n" ); document.write( "For those purposes the polar, or trigonometric, or exponential forms are much more useful.
\n" ); document.write( "For example, \"1%2Bsqrt%283%29i\" can be written using
\n" ); document.write( "its absolute value or modulus, \"r=sqrt%281%5E2%2B%28sqrt%283%29%29%5E2%29=sqrt%281%2B3%29=sqrt%284%29=2\" ,
\n" ); document.write( "and its argument \"theta\" such that \"tan%28theta%29=sqrt%283%29%2F1=sqrt%283%29\" .
\n" ); document.write( "We could say \"theta=60%5Eo\" to keep it simple, or \"theta=pi%2F3\" if you must use radians.
\n" ); document.write( "You can write \"1%2Bsqrt%283%29i\" as \"2%28cos%2860%5Eo%29%2Bi%2Asin%2860%5E0%29%29\" or as \"e%5E%28i%2Api%28%221+%2F+3%22%29%29\" .
\n" ); document.write( "All you need to remember is that when multiplying complex numbers,
\n" ); document.write( "absolute values multiply, and arguments add up.
\n" ); document.write( "
\n" ); document.write( "2) So, the solutions to
\n" ); document.write( "are numbers of the form \"r%28cos%28theta%29%2Bi%2Asin%28theta%29%29\" such that
\n" ); document.write( " .
\n" ); document.write( "That means that \"r%5E3=2\"<-->\"r=2%5E%221+%2F+3%22=root%283%2C2%29\" ,
\n" ); document.write( "and \"3theta\" is \"60%5Eo\" or a coterminal angle.
\n" ); document.write( "So, the possibilities for \"theta\" between \"0%5Eo\" and \"360%5Eo\" are
\n" ); document.write( "\"3theta=60%5Eo\" --> \"theta=20%5Eo\" ,
\n" ); document.write( "\"3theta=60%5Eo%2B360%5Eo=420\" --> \"theta=420%5Eo%2F3=140%5Eo\" ,
\n" ); document.write( "and \"3theta=60%5Eo%2B720%5Eo=780\" --> \"theta=780%5Eo%2F3=260%5Eo\" .
\n" ); document.write( "Approximate values are
\n" ); document.write( " ,
\n" ); document.write( "so we could write the answers as
\n" ); document.write( "\"2%5E%221+%2F+3%22%28cos%2820%5Eo%29%2Bi%2Asin%2820%5Eo%29%29=approximately\"\"1.1839%2Bi%2A0.4309\"
\n" ); document.write( "\"2%5E%221+%2F+3%22%28cos%28140%5Eo%29%2Bi%2Asin%28140%5Eo%29%29=approximately\"\"-0.9652%2Bi%2A0.8099\"
\n" ); document.write( "\"2%5E%221+%2F+3%22%28cos%28260%5Eo%29%2Bi%2Asin%28260%5Eo%29%29=approximately\"\"0.2188-i%2A1.2408\"
\n" ); document.write( "
\n" ); document.write( "1) The solutions to
\n" ); document.write( "are four fourth roots of \"1%28cos%2890%5Eo%29%2Bi%2Asin%2890%5Eo%29%29\" with
\n" ); document.write( "\"r=root%284%2C1%29=1\" and \"4theta=90%5Eo%2Bk%2A2pi%29\" with \"k=%220+%2C+1+%2C+2+%2C+or+3%22\" .
\n" ); document.write( "That means \"theta=22.5%5Eo\"\"or\"\"112.5%5Eo\"\"or\"\"202.5%5Eo\"\"or\"\"292.5%5Eo\" .
\n" ); document.write( "The approximate values of sine and cosine for those angles are:
\n" ); document.write( "
\n" ); document.write( "So, the four complex values of \"i%5E0.25\" are
\n" ); document.write( "\"cos%2822.5%5Eo%29%2Bi%2Asin%2822.5%29=approximately\"\"0.9239%2Bi%2A0.3827\" ,
\n" ); document.write( "\"cos%28112.5%5Eo%29%2Bi%2Asin%28112.5%29=approximately\"\"-0.3827%2Bi%2A0.9239\"
\n" ); document.write( "\"cos%2822.5%5Eo%29%2Bi%2Asin%2822.5%29=approximately\"\"-0.9239-i%2A0.3827\" , and
\n" ); document.write( "\"cos%2822.5%5Eo%29%2Bi%2Asin%2822.5%29=approximately\"\"0.3827-i%2A0.9239\"
\n" ); document.write( "
\n" ); document.write( "3) \"%28i-1%29%5E0.5=sqrt%282%29%28cos%28315%5Eo%29%2Bi%2Asin%28315%5Eo%29%29%5E%221+%2F+2%22\" has 2 values, with
\n" ); document.write( "\"r=sqrt%282%29%5E1%2F2=root%284%2C2%29=approximately1.1892\" and \"2theta=315%5Eo%2Bk%2A360%5Eo\" with \"k=%220+%2C+or+1%22\" .
\n" ); document.write( "That means \"theta=%28315%5Eo%2Bk%2A360%5Eo%29%2F2=157.5%5Eo%2Bk%2A180%5Eo\" with \"k=%220+%2C+or+1%22\" , meaning \"theta=157.5%5Eo\" or \"theta=337.5%5Eo\" .
\n" ); document.write( "Approximate values for sine and cosine of those angles are
\n" ); document.write( " ,
\n" ); document.write( "so we could write the answers as
\n" ); document.write( "\"root%284%2C2%29%28cos%28157.5%5Eo%29%2Bi%2Asin%28157.5%5Eo%29%29=approximately\"\"-1.0987%2Bi%2A0.4551\" , and
\n" ); document.write( "\"root%284%2C2%29%28cos%28337.5%5Eo%29%2Bi%2Asin%28337.5%5Eo%29%29=approximately\"\"1.0987-i%2A0.4551\" .
\n" ); document.write( "
\n" ); document.write( "4) \"9i=9%28cos%2890%5Eo%29%2Bsin%2890%5Eo%29%29\" and \"1%2Bi=sqrt%282%29%28cos%2845%5Eo%29%2Bi%2Asin%2845%5Eo%29%29\" ,
\n" ); document.write( "so their ratio can be calculated as
\n" ); document.write( "\"%289i%29%2F%281%2Bi%29\"\"%22=%22\"\"%22=%22\"\"%289%2Fsqrt%282%29%29%28cos%2890%5Eo-45%5Eo%29%2Bi%2Asin%2890%5Eo-45%5Eo%29%29\"\"%22=%22\"\"%289sqrt%282%29%2F2%29%28cos%2845%5Eo%29%2Bi%2Asin%2845%5Eo%29%29\"
\n" ); document.write( "Another way to calculate that quotient is using the conjugate of the denominator:
\n" ); document.write( "\"%289i%29%2F%281%2Bi%29\"\"%22=%22\"\"%289i%2F%281%2Bi%29%29%28%281-i%29%2F%281-i%29%29\"\"%22=%22\"\"9i%281-i%29%2F%28%281%2Bi%29%281-i%29%29\"\"%22=%22\"\"9%28i-i%5E2%29%2F%281%5E2-i%5E2%29=9%28i%2B1%29%2F%281%2B1%29\"\"%22=%22\"\"9%281%2Bi%29%2F2=9%2F2%2Bi%2A%289%2F2%29\"\"%22=%22\"\"%289sqrt%282%29%2F2%29%28cos%2845%5Eo%29%2Bi%2Asin%2845%5Eo%29%29\" .
\n" ); document.write( "Then,
\n" ); document.write( "\"%28%289i%29%2F%281%2Bi%29%29%5E%221+%2F+6%22\"\"%22=%22\"\"%289sqrt%282%29%2F2%29%5E%221+%2F+6%22%28cos%28theta%29%2Bi%2Asin%28theta%29%29\" ,
\n" ); document.write( "where \"6theta=45%5Eo%2Bk%2A360%5Eo\" with \"k=%220+%2C+1+%2C+2+%2C+3%2C+4%2C+or+5%22\" .
\n" ); document.write( "That means
\n" ); document.write( "\"theta\"\"%22=%22\"\"%2845%5Eo%2Bk%2A360%5Eo%29%2F6\"\"%22=%22\"\"7.5%5Eo%2Bk%2A60%5Eo\" .
\n" ); document.write( "\"%289sqrt%282%29%2F2%29%5E%221+%2F+6%22=approximately\"\"1.3613\" .
\n" ); document.write( "Approximate values for sine and cosine of those angles are
\n" ); document.write( "
\n" ); document.write( "So, the six complex values of \"%28%289i%29%2F%281%2Bi%29%29%5E%221+%2F+6%22\" are
\n" ); document.write( "\"%289sqrt%282%29%2F2%29%28cos%287.5%5Eo%29%2Bi%2Asin%287.5%5Eo%29%29=approximately\"\"1.3497%2Bi%2A0.1777\" ,
\n" ); document.write( "\"%289sqrt%282%29%2F2%29%28cos%2867.5%5Eo%29%2Bi%2Asin%2867.5%5Eo%29%29=approximately\"\"0.5209%2Bi%2A1.2577\" ,
\n" ); document.write( "\"%289sqrt%282%29%2F2%29%28cos%28127.5%5Eo%29%2Bi%2Asin%28127.5%5Eo%29%29=approximately\"\"-0.8287%2Bi%2A1.0800\" ,
\n" ); document.write( "\"%289sqrt%282%29%2F2%29%28cos%28187.5%5Eo%29%2Bi%2Asin%28187.5%5Eo%29%29=approximately\"\"-1.3497-i%2A0.1777\" ,
\n" ); document.write( "\"%289sqrt%282%29%2F2%29%28cos%28247.5%5Eo%29%2Bi%2Asin%28247.5%5Eo%29%29=approximately\"\"-0.5209-i%2A1.2577\" , and
\n" ); document.write( "\"%289sqrt%282%29%2F2%29%28cos%28307.5%5Eo%29%2Bi%2Asin%28307.5%5Eo%29%29=approximately\"\"0.8287-i%2A1.0800\" .
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