document.write( "Question 1116072: Ten students are to sit for an examination. Four students are doing mathematics and the other 6 different subjects. In how many ways can they be seated in a row if students doing mathematics are not to sit together? \r
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document.write( "The solution for this is 6!x7x6x5x4 but I got taught a different method and it did not work. I was taught to group all the maths people together so that there are now 7 groups. I then did 10!-7! to get the number of ways maths people not sitting together. I am really struggling with this questions and I would really appreciate it if you could post the solution and explain how you got to the answer (which is 604800). Thank you! \n" );
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Algebra.Com's Answer #731050 by KMST(5328)![]() ![]() You can put this solution on YOUR website! THE WAY THE SOLUTION WAS CALCULATED: \n" ); document.write( "I have to agree with the \n" ); document.write( " \n" ); document.write( "Get those students in the examination room, and let them pick spots in the row of chairs. \n" ); document.write( "Ask each of them to leave empty seats in between them. \n" ); document.write( "Remove the chairs that have no one sitting next to them. \n" ); document.write( "You have now \n" ); document.write( "where you can place the math students \n" ); document.write( "in a row of 6+7=13 seats. \n" ); document.write( "As each math student walks in, let them choose among the 7 empty seats. \n" ); document.write( "There are \n" ); document.write( "The first math student has 7 choices; \n" ); document.write( "the second one has 6; \n" ); document.write( "the third one has 5, \n" ); document.write( "and the last one has 4 choices. \n" ); document.write( " \n" ); document.write( "WHY \n" ); document.write( " \n" ); document.write( "so that all the members of each group are together. \n" ); document.write( "As a consequence, \n" ); document.write( " \n" ); document.write( "ANOTHER WAY: \n" ); document.write( "Out of 10 seats in a row, numbered 1 through10, \n" ); document.write( "there are only 35 ways to pick 4 non-contiguous seats for the math students: \n" ); document.write( " \n" ); document.write( "For each of those choices, you can have \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That multiplies to \n" ); document.write( " |