document.write( "Question 1116185: The senior class at a high school had a banquet that cost $150. If there had been one 5 persons less, the cost would have been $1.00 more. how many persons were at the banquet? \n" ); document.write( "
Algebra.Com's Answer #731049 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            It is a STANDARD ALGEBRA problem,  and it should be solved by Algebra method.\r
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document.write( "The standard and literal translation of the condition to Math is this equation\r\n" );
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document.write( "\"150%2F%28x-5%29\" - \"150%2Fx\" = 1   dollar.\r\n" );
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document.write( "where x is the number of people at the banquet, and each fraction in the left side is the cost (= price) per person.\r\n" );
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document.write( "Simplify and solve it\r\n" );
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document.write( "150x - 150(x-5) = x*(x-5)\r\n" );
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document.write( "750 = x^2 - 5x\r\n" );
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document.write( "x^2 - 5x - 750 = 0\r\n" );
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document.write( "(x-30)*(x+25) = 0\r\n" );
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document.write( "The only positive root x= 30 works as the solution to the problem.\r\n" );
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document.write( "Answer.  30 persons.\r\n" );
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document.write( "Check.   \"150%2F25\" - \"150%2F30\" = 6 - 5 = 1.   ! Correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "Again:   It is a standard Algebra problem,  and a well trained student must know how to solve it algebraically.\r
\n" ); document.write( "\n" ); document.write( "            The translation from the condition to Math is the key.  The rest is just technique.\r
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\n" ); document.write( "\n" ); document.write( "To see  MANY  OTHER  SIMILAR  SOLVED  problems,  look into the lesson\r
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