document.write( "Question 1116188: A picture that is 18 inches by 12 inches has a frame of uniform width whose area is equal to that of the picture. Find the width o the frame. \n" ); document.write( "
Algebra.Com's Answer #731017 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A picture that is 18 inches by 12 inches has a frame of uniform width whose area is equal to that of the picture.
\n" ); document.write( " Find the width of the frame.
\n" ); document.write( ":
\n" ); document.write( "find the area of the picture
\n" ); document.write( "18 * 12 = 216 sq/in
\n" ); document.write( "let x = the width of the frame
\n" ); document.write( "then the overall dimensions including the frame will be
\n" ); document.write( "(2x+18) by (2x+12)
\n" ); document.write( ":
\n" ); document.write( "Overall area - picture area = frame area
\n" ); document.write( "(2x+18)*(2x+12) - 216 = 216
\n" ); document.write( "FOIL
\n" ); document.write( "4x^2 + 24x + 36x + 216 - 216 = 216
\n" ); document.write( "A quadratic equation
\n" ); document.write( "4x^2 + 60x - 216 = 0
\n" ); document.write( "simplify divide by 4
\n" ); document.write( "x^2 + 15x - 54 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x+18)(x-3) = 0
\n" ); document.write( "the positive solution is all we want here
\n" ); document.write( "x = 3 inches is the width of the frame \n" ); document.write( "
\n" );