document.write( "Question 1116106: I'm trying to brush up on my math skills 45 years after high school. Most of it is pretty basic but this one has me stumped.\r
\n" ); document.write( "\n" ); document.write( "( b + a ) / ab = 1 / f
\n" ); document.write( "solve for b\r
\n" ); document.write( "\n" ); document.write( "I've mashed it all around but I just can't tease out the b. I even tried working backward from the answer. How is this done? The answer in the back of the book is:\r
\n" ); document.write( "\n" ); document.write( "b = fa / ( a - f ) or b = -fa / ( f - a )\r
\n" ); document.write( "\n" ); document.write( "if you're interested.\r
\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Jim
\n" ); document.write( "

Algebra.Com's Answer #730933 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"%28b+%2B+a%29%2F%28ab%29+=+1%2Ff\"
\n" ); document.write( "cross multiply
\n" ); document.write( "f(b+a) = ab
\n" ); document.write( "fb + fa = ab
\n" ); document.write( "fb - ab = -fa
\n" ); document.write( "Factor out b
\n" ); document.write( "b(f-a) = -fa
\n" ); document.write( "b = \"-%28fa%29%2F%28f-a%29\"
\n" ); document.write( "
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