document.write( "Question 1116014: The quadrilateral ABCD has vertices A(1,0), B(3,1), C(4,3) and D(2,2).
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document.write( "a) Show that the intervals AC and BD bisect each other.
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document.write( "b) What can be concluded about the type of quadrilateral ABCD? \n" );
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Algebra.Com's Answer #730920 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "part (a) \n" ); document.write( "Diagonal AC contains the points (1,0) and (4,3); the equation of the line through those two points is y = x-1. \n" ); document.write( "Diagonal BD contains the points (3,1) and (2,2); the equation of the line through those two points is y = -x+4. \n" ); document.write( "The intersection of the two diagonals is the common point on the graphs of y = x-1 and y = -x+4; that point is (2.5,1.5). \n" ); document.write( "The midpoints of AC and BD are also both (2.5,1.5). \n" ); document.write( "The intersection of the two diagonals is the midpoint of both, so the diagonals bisect each other. \n" ); document.write( "part (b) \n" ); document.write( "The fact that the diagonals bisect each other means the quadrilateral is a parallelogram. \n" ); document.write( "In fact, the quadrilateral is a rhombus, because the two diagonals are perpendicular to each other (the product of their slopes is -1). \n" ); document.write( "But we were not asked to show that the diagonals are perpendicular; only knowing that the diagonals bisect each other only tells us that the quadrilateral is a parallelogram. \n" ); document.write( " |