document.write( "Question 80665: The difference of two numbers is 33. The second is 7 less than 3 times the first. What are the two numbers? \n" ); document.write( "

Algebra.Com's Answer #730911 by ikleyn(52788) $\"\"$ $\"About$

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document.write( "x = first    y = second \r\n" );
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document.write( "x - y = 33     (1)    according to the condition\r\n" );
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document.write( "y = 3x-7       (2)    according to the condition\r\n" );
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document.write( "Substitute (2) into (1) to get \r\n" );
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document.write( "x - (3x-7) = 33\r\n" );
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document.write( "x - 3x + 7 = 33\r\n" );
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document.write( "-2x = 33 - 7\r\n" );
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document.write( "-2x = 26\r\n" );
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document.write( "x = -13  ====>  y = 3x-7 = 3*(-13) - 7 = -39-7 = -46.\r\n" );
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document.write( "Answer.  The numbers are -13 (first) and -46 (second).\r\n" );
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\n" ); document.write( "\n" ); document.write( "Notice: The words \"the difference of two numbers\" may mean (x-y) OR (y-x) - it is not determined by an unique way.\r
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\n" ); document.write( "\n" ); document.write( "So, playing with the difference y-x = 33, you will get another answer.\r
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\n" ); document.write( "\n" ); document.write( "Try it and get your own answer/solution.\r
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