document.write( "Question 80665: The difference of two numbers is 33. The second is 7 less than 3 times the first. What are the two numbers? \n" ); document.write( "
Algebra.Com's Answer #730906 by Shin123(626)\"\" \"About 
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x=first y=second \r
\n" ); document.write( "\n" ); document.write( "\"x-y=33\"\r
\n" ); document.write( "\n" ); document.write( "\"y=3x-7\" in other words,\r
\n" ); document.write( "\n" ); document.write( "\"y-7=3x\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y-7%29%2Bx=4x\" \r
\n" ); document.write( "\n" ); document.write( "\"%281%2F4y-7%29%2Bx=x\"\r
\n" ); document.write( "\n" ); document.write( "\"1%2F4y-7=0\" so\r
\n" ); document.write( "\n" ); document.write( "\"y=28\"\r
\n" ); document.write( "\n" ); document.write( "\"x=28%2B33=61=x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=61\" \"y=28\" I don’t think I solved it correctly.
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