document.write( "Question 1116038: Evaluate the following expressions:
\n" ); document.write( " a. log downward exponient 13 1\r
\n" ); document.write( "\n" ); document.write( " b. ln e upward exponient 8\r
\n" ); document.write( "\n" ); document.write( " c. log downward exponient 27 27\r
\n" ); document.write( "\n" ); document.write( " d. log downward exponient 9 27
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Algebra.Com's Answer #730891 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "\"exponient\" should be \"exponent\"

\n" ); document.write( "\"log downward exponient b...\" should be \"log, base b...\"

\n" ); document.write( "\"ln\" means \"log, base e\"

\n" ); document.write( "\"log a upward exponient b...\" simply means \"log of a^b\"

\n" ); document.write( "So....

\n" ); document.write( "a. log downward exponient 13 1 --> log, base 13, of 1
\n" ); document.write( "\"log%2813%2C1%29\" is 0, because \"13%5E0+=+1\"

\n" ); document.write( "b. ln e upward exponient 8 --> log, base e, of e^8
\n" ); document.write( "By definition \"log%28e%2C%28e%5E8%29%29+=+8\"

\n" ); document.write( "c. log downward exponient 27 27 --> log, base 27, of 27
\n" ); document.write( "\"log%2827%2C27%29\" is 1, because \"27%5E1+=+27\"

\n" ); document.write( "d. log downward exponient 9 27 --> log, base 9, of 27
\n" ); document.write( "\"log%289%2C27%29+=+log%28%283%5E2%29%2C%283%5E3%29%29\" is 3/2, because \"%283%5E2%29%5E%283%2F2%29+=+3%5E3\"
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