document.write( "Question 1115970: Evaluate the following expressions:
\n" ); document.write( "a. log downward exponient 13 1
\n" ); document.write( "b. ln e upward exponient 8
\n" ); document.write( "c. log downward exponient 27 27
\n" ); document.write( "d. log downward exponient 9 27
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Algebra.Com's Answer #730799 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
\"downward exponient\"
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\n" ); document.write( "What's that? \r
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\n" ); document.write( "\n" ); document.write( "Here is a GUESS for two of the examples.\r
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\n" ); document.write( "\n" ); document.write( "EXAMPLE c
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\n" ); document.write( "Your base is 27 and your \"antilog\" is 27. The \"logarithm\" you are looking for is the exponent. If your log is variable x, then you could also say \"27%5Ex=27\"-------OBVIOUS!
\n" ); document.write( "\"log%2827%2C27%29\"
\n" ); document.write( "\"highlight%281%29\"
\n" ); document.write( "(do you understand why?)\r
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\n" ); document.write( "\n" ); document.write( "EXAMPLE d
\n" ); document.write( "\"log%289%2C27%29\"-------the most likely correct notation
\n" ); document.write( "\"x=log%289%2C3%5E3%29\"--------giving a variable to the \"logarithm\", for help when converting into exponential form
\n" ); document.write( "\"9%5Ex=3%5E3\"---------------now in exponential form
\n" ); document.write( "\"%283%5E2%29%5Ex=3%5E3\"\r
\n" ); document.write( "\n" ); document.write( "\"3%5E%282x%29=3%5E3\"\r
\n" ); document.write( "\n" ); document.write( "\"2x=3\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=3%2F2%29\"
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\n" ); document.write( "These steps should now be clear.
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