document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115933>Question 1115933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The radius of circle B  is 2.5  times the radius of circle A. If the area of circle A  is 8 square yards what is the  area of circle B? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #730766 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=730766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "You don't need to do any arithmetic using the formula for the area of a circle.<br><BR>\n" );
document.write( "All circles are similar; in similar figures, if the ratio of lengths is a:b, the ratio of areas is a^2:b^2.<br><BR>\n" );
document.write( "The ratio of lengths (radii of the two circles) is given as 2.5:1; so the ratio of areas is (2.5)^2:1^2 = 6.25:1<br><BR>\n" );
document.write( "Then the area of the larger circle is 8*6.25 = 50 square yards. </SPAN>\n" );
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