document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115933>Question 1115933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The radius of circle B  is 2.5  times the radius of circle A. If the area of circle A  is 8 square yards what is the  area of circle B? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #730756 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=730756\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The radius of circle B is 2.5 times the radius of circle A. If the area of circle A is 8 square yards what is the area of circle B? <BR>\n" );
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document.write( "Area of circle A = pi*r^2 = 8<BR>\n" );
document.write( "So radius = sqrt[8/pi]<BR>\n" );
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document.write( "Radius of circle B = 2.5*sqrt[8/pi]<BR>\n" );
document.write( "Area of circle B = pi[2.5*sqrt[8/pi]]^2= pi[6.25*8/pi] = 6.25*8 = 50 sq yrds<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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