document.write( "Question 1115925: (8x^3 - 6x^2 - 7x + 1)/(2x-3) \n" ); document.write( "
Algebra.Com's Answer #730754 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
You start the same way as if normal base-ten numbers division:
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document.write( "2x-3   |    8x^3     -6x^2     -7x     +1\r\n" );
document.write( "       |\r\n" );
document.write( "       |\r\n" );
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\n" ); document.write( "\n" ); document.write( "The entire process:
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document.write( "             4x^2      3x       1\r\n" );
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document.write( "2x-3   |    8x^3     -6x^2     -7x     +1\r\n" );
document.write( "       |\r\n" );
document.write( "       |    8x^3     -12x^2\r\n" );
document.write( "        --------------------\r\n" );
document.write( "            0         6x^2    -7x\r\n" );
document.write( "                      6x^2   -9x\r\n" );
document.write( "                     --------------\r\n" );
document.write( "                       0      2x    +1\r\n" );
document.write( "                              2x   -3\r\n" );
document.write( "                              -----------\r\n" );
document.write( "                              0     4\r\n" );
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\n" ); document.write( "\n" ); document.write( "QUOTIENT: \"4x%5E2%2B3x%2B1\"
\n" ); document.write( "REMAINDER: \"4\"\r
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\n" ); document.write( "\n" ); document.write( "MEANING: \"4x%5E2%2B3x%2B1%2B4%2F%282x-3%29\"
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