document.write( "Question 1115882: express the probability as a percent.
\n" ); document.write( "during the 2011-12 NBA basketball season, Kevin Durant made 86% of the free throws that he attempted. what is the probability that he would make exactly nine of his next ten free throws? \n" ); document.write( "

Algebra.Com's Answer #730724 by rothauserc(4718) $\"\"$ $\"About$

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use the binomial probability formula
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\n" ); document.write( "Probability (P) (k successes in n trials) = nCk * p^k * (1-p)^(n-k), where nCk = n! / (k! * (n-k)!)
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\n" ); document.write( "for this problem, n=10, k=9, p=0.86
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\n" ); document.write( "P (9 successes in 10 trials) = 10C9 * (0.86)^9 * (1-0.86)^(10-9) =
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\n" ); document.write( "(10!/(9! * (10-9)!) * 0.2573 * 0.14 =
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\n" ); document.write( "10 * 0.2573 *0.14 = 0.3602 approximately 0.36
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\n" ); document.write( "probability Kevin Durant will make 9 free throws out of the next 10 is 0.36
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