document.write( "Question 1115859: A plant food is to be made from three chemicals. The combined amounts of the first two chemicals must be 70​% of the resulting mix. The second and third chemicals must be in the ratio of 4 to 3 by weight. How much of each chemical is needed to make 700 kg of the plant​ food? \n" ); document.write( "
Algebra.Com's Answer #730689 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
First, second, and third ingredients
\n" ); document.write( "x, y, z\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2By%29%2F700=0.7\"
\n" ); document.write( "\"x%2By=700%2A0.7\"
\n" ); document.write( "\"x%2By=7%2A7%2A100%2A0.1\"
\n" ); document.write( "\"x%2By=49%2A10\"
\n" ); document.write( "\"x%2By=490\"
\n" ); document.write( "-
\n" ); document.write( "\"y%2Fz=4%2F3\"
\n" ); document.write( "-
\n" ); document.write( "\"x%2By%2Bz=700\"\r
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\n" ); document.write( "\n" ); document.write( "The three equations from the description are:
\n" ); document.write( "\"system%28x%2By%2Bz=700%2Cx%2By=490%2C3y=4z%29\"\r
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\n" ); document.write( "\n" ); document.write( "Note that the expression \"x%2By\" occurs twice in the list of equations.\r
\n" ); document.write( "\n" ); document.write( "\"system%28%28x%2By%29%2Bz=700%2Cx%2By=490%29\"\r
\n" ); document.write( "\n" ); document.write( "Subtract the corresponding members to find \"z=700-490\"
\n" ); document.write( "\"highlight%28z=210%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"3y=4z\"
\n" ); document.write( "\"y=4z%2F3\"
\n" ); document.write( "\"y=4%2A210%2F3\"
\n" ); document.write( "\"y=4%2A70\"
\n" ); document.write( "\"highlight%28y=280%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=490\"
\n" ); document.write( "\"x=490-y\"
\n" ); document.write( "\"x=490-280\"
\n" ); document.write( "\"highlight%28x=210%29\"\r
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\r\n" );
document.write( "    MATERIAL           KILOGRAMS\r\n" );
document.write( "x   first chemical      210\r\n" );
document.write( "y   second chemical     280\r\n" );
document.write( "z   third chemical      210\r\n" );
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