document.write( "Question 100335This question is from textbook Algebra 2
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document.write( ": Use substitution to solve each system of equations.\r
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document.write( "a+b+c=6
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document.write( "3a-b+c=8
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document.write( "2b=c \n" );
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Algebra.Com's Answer #73065 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! C=2B \n" ); document.write( "A+B+2B=6 OR A+3B=6 \n" ); document.write( "3A-B+2B=8 OR 3A+B=8 NOW MULTIPLY THIS EQUATION BY -3 & ADD THE LAST 2 EQUATIONS. \n" ); document.write( "THIS STEP IS NECESSARY TO ELIMINATE THE B TERM SO WE CAN SOLVE FOR THE A TERM. \n" ); document.write( "A+3B=6 \n" ); document.write( "-9A-3B=-24 \n" ); document.write( "----------------------- \n" ); document.write( "-8A=-18 \n" ); document.write( "A=-18/-8 \n" ); document.write( "A=2.25 ANSWER. \n" ); document.write( "2.25+3B=6 \n" ); document.write( "3B=6-2.25 \n" ); document.write( "3B=3.75 \n" ); document.write( "B=3.75/3 \n" ); document.write( "B=1.25 ANSWER. \n" ); document.write( "C=2*1.25 \n" ); document.write( "C=2.5 ANSWER. \n" ); document.write( " |