document.write( "Question 1115791: Find the latus rectum of given equation y^2+8x-6y+25=0 \n" ); document.write( "
Algebra.Com's Answer #730623 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the latus rectum of given equation y^2+8x-6y+25=0 \n" ); document.write( "-------- \n" ); document.write( "y^2-6y+9 = -8x-16 \n" ); document.write( "-8(x+2) = (y-3)^2 \n" ); document.write( "---- \n" ); document.write( "4p = -8 \n" ); document.write( "p = -2 \n" ); document.write( "----- \n" ); document.write( "You have a parabola opening to the left with vertex at (-2,3) \n" ); document.write( "The focus is 2 to the left of (-2,3) and corresponds to the \n" ); document.write( "line y = -4. \n" ); document.write( "The latus rectum is a vertical line segment passing thru the focus. \n" ); document.write( "Length of the latus rectum = |4p| = 8 \n" ); document.write( "---- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |