document.write( "Question 1115791: Find the latus rectum of given equation y^2+8x-6y+25=0 \n" ); document.write( "
Algebra.Com's Answer #730623 by stanbon(75887)\"\" \"About 
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Find the latus rectum of given equation y^2+8x-6y+25=0
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\n" ); document.write( "y^2-6y+9 = -8x-16
\n" ); document.write( "-8(x+2) = (y-3)^2
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\n" ); document.write( "4p = -8
\n" ); document.write( "p = -2
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\n" ); document.write( "You have a parabola opening to the left with vertex at (-2,3)
\n" ); document.write( "The focus is 2 to the left of (-2,3) and corresponds to the
\n" ); document.write( "line y = -4.
\n" ); document.write( "The latus rectum is a vertical line segment passing thru the focus.
\n" ); document.write( "Length of the latus rectum = |4p| = 8
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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