document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115770>Question 1115770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of circle  center at (1,3) and tangent to the line 5x-12y=8. please explain. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #730606 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=730606\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of circle  center at (1,3) and tangent to the line 5x-12y=8.<BR>\n" );
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document.write( "You can find the equation of the line perpendicular to the given line thru the point.<BR>\n" );
document.write( "then find the distance from the point to the line, that's the radius.<BR>\n" );
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document.write( "Then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-1%29%5E2+%2B+%28y-3%29%5E2+=+r%5E2 ALIGN=MIDDLE  ALT=\"%28x-1%29%5E2+%2B+%28y-3%29%5E2+=+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the circle.<BR>\n" );
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document.write( "Or, use<BR>\n" );
document.write( "5x-12y-8 = 0<BR>\n" );
document.write( "a = 5, b = -12, c = -8<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+ABS%28a%2Ax%5B0%5D+%2B+b%2Ay%5B0%5D+%2B+c%29%2Fsqrt%28a%5E2%2Bb%5E2%29 ALIGN=MIDDLE  ALT=\"r+=+ABS%28a%2Ax%5B0%5D+%2B+b%2Ay%5B0%5D+%2B+c%29%2Fsqrt%28a%5E2%2Bb%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > to find the distance.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%5B0%5D+y%5B0%5D%29 ALIGN=MIDDLE  ALT=\"%28x%5B0%5D+y%5B0%5D%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the point.<BR>\n" );
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