document.write( "Question 1115765: if the area of the rectangle is 42in squared, find the value of x\r
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Algebra.Com's Answer #730598 by MathLover1(20850)\"\" \"About 
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if the area of the rectangle is \"42\" in squared, find the value of \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"L=x%2B8+\"->corrected
\n" ); document.write( "\"W=x-3\"\r
\n" ); document.write( "\n" ); document.write( "\"A=L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"42=%28x%2B8%29%2A%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"42=x%5E2-3x+%2B8x-24\"\r
\n" ); document.write( "\n" ); document.write( "\"0=x%5E2%2B5x-24-42\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B5x-66=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B11x-6x-66=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B11x%29-%286x%2B66%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%28x%2B11%29-6%28x%2B11%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+6%29+%28x+%2B+11%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "\"x+-+6%29++=+0\"->\"x=6\"\r
\n" ); document.write( "\n" ); document.write( "(\"+%28x+%2B+11%29+=+0\"->\"x=-11\" since we are looking for length and width, disregard negative solution\r
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\n" ); document.write( "\n" ); document.write( "so, your solution is: \"highlight%28x+=+6%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=x%2B8+\"->\"L=6%2B8+\"->\"highlight%28L=14%29+\"
\n" ); document.write( "\"W=x-3\"->\"W=6-3\"->\"highlight%28W=3%29\"\r
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