document.write( "Question 1115766: The notation n! = n•(n-1)•(n–2)• • • • • •3•2•1. For example, 5! = 5•4•3•2•1 = 120. How many zeroes occur at the end of the expanded numeral for 100!? \n" ); document.write( "
Algebra.Com's Answer #730596 by MathLover1(20850)\"\" \"About 
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The number of trailing zeros in the decimal representation of \"n%21\", the factorial of a non-negative integer \"n\", can be determined with this formula:\r
\n" ); document.write( "\n" ); document.write( "\"n%2F5%2Bn%2F5%5E2%2Bn%2F5%5E3\"+...+\"n%2F5%5Ek\" where \"k\" must be chosen such that \"5%5E%28k%2B1%29%3En\"\r
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\n" ); document.write( "\n" ); document.write( "so, \"100%21\" has \"100%2F5%2B100%2F5%5E2=100%2F5%2B100%2F25=20%2B4=24\" trailing zeros
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