document.write( "Question 1115763: The doubling period of bacterial population in 20 minutes. At time t = 120 minutes, the bacterial population was 6000.
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document.write( "What was the initial population at time t = 0?
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document.write( "Find the size of the bacterial population after 4 hours?
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Algebra.Com's Answer #730594 by rothauserc(4718) You can put this solution on YOUR website! The population doubles every 20 minutes, in 120/20 there are 6 time periods \n" ); document.write( ": \n" ); document.write( "Therefore initial population is (6000/2^6) = 93.75 approximately 94 \n" ); document.write( ": \n" ); document.write( "in 240 minutes there are 240/20 = 12 time periods \n" ); document.write( ": \n" ); document.write( "we know the population is 6000 at time 120 \n" ); document.write( ": \n" ); document.write( "there are 120/20 = 6 additional time periods \n" ); document.write( ": \n" ); document.write( "population after 240 minutes = 6000 * 2^6 = 384,000 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |