document.write( "Question 1115763: The doubling period of bacterial population in 20 minutes. At time t = 120 minutes, the bacterial population was 6000.
\n" ); document.write( "What was the initial population at time t = 0?
\n" ); document.write( "Find the size of the bacterial population after 4 hours?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #730594 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
The population doubles every 20 minutes, in 120/20 there are 6 time periods
\n" ); document.write( ":
\n" ); document.write( "Therefore initial population is (6000/2^6) = 93.75 approximately 94
\n" ); document.write( ":
\n" ); document.write( "in 240 minutes there are 240/20 = 12 time periods
\n" ); document.write( ":
\n" ); document.write( "we know the population is 6000 at time 120
\n" ); document.write( ":
\n" ); document.write( "there are 120/20 = 6 additional time periods
\n" ); document.write( ":
\n" ); document.write( "population after 240 minutes = 6000 * 2^6 = 384,000
\n" ); document.write( ":
\n" ); document.write( "
\n" ); document.write( "
\n" );