document.write( "Question 1115763: The doubling period of bacterial population in 20 minutes. At time t = 120 minutes, the bacterial population was 6000.
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Algebra.Com's Answer #730589 by ikleyn(52864) $\"\"$ $\"About$

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\n" ); document.write( "The doubling period of bacterial population $\"highlight%28cross%28in%29%29\"$ is 20 minutes. At time t = 120 minutes, the bacterial population was 6000.
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\n" ); document.write( "Find the size of the bacterial population after 4 hours?
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\n" ); document.write( "\n" ); document.write( " * * * I read your condition as \"4 hours after t= 120 minutes\" * * *.\r
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document.write( "1)  120 minutes = 6 times 20 minutes = 6 times doubling period.\r\n" );
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document.write( "    Therefore,   =  = 94 (approximately).\r\n" );
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document.write( "2)  4 hours = 4*60 minutes = 4*3 = 12 doubling periods.\r\n" );
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document.write( "    Therefore,   =  =  24576000.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "Be aware: The solution by @rothauserc was totally W R O N G ! \r
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\n" ); document.write( "\n" ); document.write( " His error was in that the \"linear rate\", as he defined it, was irrelevant to the exponential rate.\r
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