document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115710>Question 1115710</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help<BR>\n" );
document.write( "Given that the right triangle ABC as shown, fill in the values of tan &#952; and sec &#952;, and prove in general that 1 + tan^2 &#952; = sec^2 &#952; <BR>\n" );
document.write( "Tan &#952; =_____<BR>\n" );
document.write( "Sec &#952;=_____ <BR>\n" );
document.write( "Here is a picture of the problem <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #730544 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=730544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The tangent is a/b<BR>\n" );
document.write( "The secant is the reciprocal of the cosine and is c/b<BR>\n" );
document.write( "1+(a^2/b^2)=(b^2+a^2)/b^2=c^2/b^2, because a^2+b^2=c^2<BR>\n" );
document.write( "c/b is the secant, so (c/b)^2 theta is sec^2, theta<BR>\n" );
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