document.write( "Question 1115646: At a college play production, 360 tickets were sold. The ticket prices were $8, $10, and $12 and the total income from ticket sales was 3436. How many tickets of each type were wold if the number of $8 tickets sold was twice the number of $12 tickets sold? \n" ); document.write( "

Algebra.Com's Answer #730491 by ikleyn(52787) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " It is a typical problem to solve using a single unknown.\r
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document.write( "Let x = # of $12 tickets.\r\n" );
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document.write( "Then the number of $8 tickets is 2x, according to the condition.\r\n" );
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document.write( "Then the number of $10 tickets is  (360 - x - 2x) = (360-3x).\r\n" );
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document.write( "Now your \"money\" equation is\r\n" );
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document.write( "8*(2x) + 10*(360-3x) + 12*x = 3436,   or\r\n" );
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document.write( "16x + 3600 - 30x + 12x = 3436\r\n" );
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document.write( "-2x = 3436 - 3600 = - 164  ====>  x = 82.\r\n" );
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document.write( "Answer.  82 $12 tickets;  2*82 = 164 $8 tickets;  and  (360-3*82) = 114 $10 tickets.\r\n" );
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document.write( "Check.   12*82 + 8*164 + 10*114 = 3436 dollars.    ! Correct !\r\n" );
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