document.write( "Question 1115599: edgar rode 60 miles on his electric bicycle at a certain speed. had he been able to travel 5 miles per hour faster, he would have taken 1 hour less time. how fast did edgar travel \n" ); document.write( "
Algebra.Com's Answer #730433 by Boreal(15235)\"\" \"About 
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speed=v
\n" ); document.write( "v*time=distance
\n" ); document.write( "v*t=60
\n" ); document.write( "(v+5)*(t-1)=60, because one hour less time to go the same distance at 5 mph faster.
\n" ); document.write( "t=60/v
\n" ); document.write( "t-1=60/(v+5)
\n" ); document.write( "t=(60+v+5)/(v+5), common denominator
\n" ); document.write( "Set the two t s equal to each other
\n" ); document.write( "(60/v)=(60+v+5)/(v+5)
\n" ); document.write( "cross-multiply
\n" ); document.write( "60(v+5)=v(65+v)
\n" ); document.write( "60v+300=65v+v^2
\n" ); document.write( "0=v^2+5v-300
\n" ); document.write( "(v+20)(v-15)=0
\n" ); document.write( "v=15 mph only positive root, 4 hours to go 60 miles and
\n" ); document.write( "3 hours to go 60 miles at 20 mph.\r
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