document.write( "Question 1115560: A painter can paint a building in 15 days and a co worker can do the same job in 10 days. If the first painter starts and 3 days later the co worker Joins in to help finish the job, how many does it take to paint the building? \n" ); document.write( "

Algebra.Com's Answer #730409 by ikleyn(52797) $\"\"$ $\"About$

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document.write( "1.  From the condition, the first painter makes    of the job per day.\r\n" );
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document.write( "    The second makes   of the job per day.\r\n" );
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document.write( "    Hence, working together, they make   =  =  =   of the job per day.\r\n" );
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document.write( "    It is their combined rate of work.\r\n" );
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document.write( "2.  Working for 3 days, the first painter made   =  of the job.\r\n" );
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document.write( "    Hence,   of the job remained.\r\n" );
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document.write( "3.  Thus the two, working together, must complete   of the job.\r\n" );
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document.write( "    Since their combined rate of work is   of the whole work per day,\r\n" );
document.write( "    it will take them    =  =  of the day =  days = 4.8 days.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer. The schedule is this: first painter works 3 days, and then the two work together for 4.8 days.\r
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