document.write( "Question 1115558: A painter can paint a building in 15 days and a co-worker can do the same job in 10 days. If the first painter starts and 3 days later the co-worker joins in to help finish the job, how many days does it take to paint the building? \n" ); document.write( "
Algebra.Com's Answer #730408 by ikleyn(52786)\"\" \"About 
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document.write( "1.  From the condition, the first painter makes  \"1%2F15\"  of the job per day.\r\n" );
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document.write( "    The second makes \"1%2F10\"  of the job per day.\r\n" );
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document.write( "    Hence, working together, they make  \"1%2F15+%2B+1%2F10\" = \"2%2F30+%2B+3%2F30\" = \"5%2F30\" = \"1%2F6\"  of the job per day.\r\n" );
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document.write( "    It is their combined rate of work.\r\n" );
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document.write( "2.  Working for 3 days, the first painter made  \"3%2F15\" = \"1%2F5\" of the job.\r\n" );
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document.write( "    Hence,  \"4%2F5\" of the job remained.\r\n" );
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document.write( "3.  Thus the two, working together, must complete  \"4%2F5\" of the job.\r\n" );
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document.write( "    Since their combined rate of work is  \"1%2F5\" of the whole work per day,\r\n" );
document.write( "    it will take them   \"%28%284%2F5%29%29%2F%28%281%2F6%29%29\" = \"%286%2A4%29%2F5\" = \"24%2F5\" of the day = \"4\"\"4%2F5\" days = 4.8 days.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer.  The schedule is this:  first painter works 3 days,  and then the two work together for  4.8 days.\r
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