document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115543>Question 1115543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the mean of ten positive numbers is 16. When another number is added the mean is 18. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #730407 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13215)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=730407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative method I like to use when working with means (averages) where the numbers are relatively simple numbers.<br><BR>\n" );
document.write( "The individual numbers don't matter; since the mean of the original 10 numbers is 16, we can let each of them be equal to 16.<br><BR>\n" );
document.write( "After the 11th number is added, the mean of all 11 numbers is 18.<br><BR>\n" );
document.write( "Each of the 10 original numbers is 2 short of that mean; that means the sum of those original 10 numbers is 20 short of the total required to get the new mean of 18.<br><BR>\n" );
document.write( "That means the 11th number, to balance the shortfall from the original 10 numbers, must be 20 MORE than the new mean.<br><BR>\n" );
document.write( "So the 11th number is 18+20 = 38.<BR>\n" );
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