document.write( "Question 1115542: An accident in 1986 at the Chernobyl nuclear plant in Ukraine released a large amount of plutonium (Pu-239) into the atmosphere. The half-life of Pu-239 is about 24,110 years. Find the decay constant. Use the function N(t)=Noe^-kt to find what remains of an initial 20 grams of Pu-239 after 5000 years. How long will it take for these 20 grams to decay to 1 gram? \n" ); document.write( "
Algebra.Com's Answer #730399 by josgarithmetic(39620)\"\" \"About 
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N(t)=Noe^-kt\r
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\n" ); document.write( "\n" ); document.write( "Do it this way in pure text
\n" ); document.write( "N(t)=N[o]e^(-kt)\r
\n" ); document.write( "\n" ); document.write( "\"N%28t%29=N%5Bo%5De%5E%28-kt%29\"\r
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\n" ); document.write( "\n" ); document.write( "Reassigning variables for typewriting convenience:
\n" ); document.write( "\"N=ne%5E%28-kt%29\", N for function and n for initial quantity\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28N%29=ln%28ne%5E%28-kt%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%28N%29=ln%28n%29%2B%28-kt%29%2A1\"\r
\n" ); document.write( "\n" ); document.write( "\"-kt%2Bln%28n%29=ln%28N%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-kt=ln%28N%29-ln%28n%29\"\r
\n" ); document.write( "\n" ); document.write( "\"kt=ln%28n%29-ln%28N%29\"\r
\n" ); document.write( "\n" ); document.write( "\"k=%28ln%28n%29-ln%28N%29%29%2Ft\"\r
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\n" ); document.write( "\n" ); document.write( "You were given half-life is 24110 years. This means \"ln%28n%2FN%29=ln%281%2F%281%2F2%29%29=ln%282%29\";\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28k=ln%282%29%2Ft%29\"
\n" ); document.write( "and
\n" ); document.write( "\"k=ln%282%29%2F24110\"
\n" ); document.write( "\"highlight%28k=0.00002875%29\"\r
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\n" ); document.write( "\n" ); document.write( "The original model, \"highlight_green%28highlight%28N%28t%29=N%5Bo%5De%5E%28-0.00002875t%29%29%29\"
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