document.write( "Question 100290: Lois rode her bike to visit a friend. She traveled at 10 mi/hr. While she was there, it began to rain. Her friend drove her home in a car traveling at 25 mi/hr. Lois took 1.5 hr longer to go to her friend's than to return home. How many hours did it take Lois to ride to her friend's house? Need assistance in writing an equation as well as solving the problem. Thanks in advance from a confused parent! \n" ); document.write( "

Algebra.Com's Answer #73039 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
distance(d)=rate(r) times time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let t=time it took Lois to ride home in the car
\n" ); document.write( "Then (t+1.5)=time it took Lois to bike to her friends\r
\n" ); document.write( "\n" ); document.write( "(1) distance she travelled on a bike=rt=10*(t+1.5)
\n" ); document.write( "(2) distance she travelled back in the car=25*t\r
\n" ); document.write( "\n" ); document.write( "Now we know that (1)distance going=(2)distance coming back in the car. So:\r
\n" ); document.write( "\n" ); document.write( "10(t+1.5)=25t get rid of parens\r
\n" ); document.write( "\n" ); document.write( "10t+15=25t subtract 10t from both sides\r
\n" ); document.write( "\n" ); document.write( "10t-10t+15=25t-10t collect like terms\r
\n" ); document.write( "\n" ); document.write( "15=15t divide both sides by 15\r
\n" ); document.write( "\n" ); document.write( "t=1 hour time it took to ride home in the car\r
\n" ); document.write( "\n" ); document.write( "t+1.5=1+1.5=2.5 hrs-------------------------time it took biking to her friends\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "2.5*10=1*25
\n" ); document.write( "25=25\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( "

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