document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115552>Question 1115552</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangular wall of a barn is 80 square feet. Its length is 12 feet longer than twice its width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #730389 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=730389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangular wall of a barn is 80 square feet. Its length is 12 feet longer than twice its width? What are the dimensions?<BR>\n" );
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document.write( "Width = W<BR>\n" );
document.write( "Length = 2W+12<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "W(2W+12) = 80<BR>\n" );
document.write( "2W^2 + 12W - 80 = 0<BR>\n" );
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document.write( "W^2 + 6W - 40 = 0<BR>\n" );
document.write( "(W+10)(W-4) = 0<BR>\n" );
document.write( "Positive solution::<BR>\n" );
document.write( "Width = 4 ft<BR>\n" );
document.write( "Length = 2*4+12 = 20 ft<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "  </SPAN>\n" );
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